Optimal. Leaf size=137 \[ -\frac {a b \left (19 a^2+16 b^2\right ) \cos (e+f x)}{6 f}-\frac {b^2 \left (26 a^2+9 b^2\right ) \sin (e+f x) \cos (e+f x)}{24 f}+\frac {1}{8} x \left (8 a^4+24 a^2 b^2+3 b^4\right )-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f} \]
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Rubi [A] time = 0.15, antiderivative size = 137, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2656, 2753, 2734} \[ -\frac {a b \left (19 a^2+16 b^2\right ) \cos (e+f x)}{6 f}-\frac {b^2 \left (26 a^2+9 b^2\right ) \sin (e+f x) \cos (e+f x)}{24 f}+\frac {1}{8} x \left (24 a^2 b^2+8 a^4+3 b^4\right )-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f} \]
Antiderivative was successfully verified.
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Rule 2656
Rule 2734
Rule 2753
Rubi steps
\begin {align*} \int (a+b \sin (e+f x))^4 \, dx &=-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac {1}{4} \int (a+b \sin (e+f x))^2 \left (4 a^2+3 b^2+7 a b \sin (e+f x)\right ) \, dx\\ &=-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}+\frac {1}{12} \int (a+b \sin (e+f x)) \left (a \left (12 a^2+23 b^2\right )+b \left (26 a^2+9 b^2\right ) \sin (e+f x)\right ) \, dx\\ &=\frac {1}{8} \left (8 a^4+24 a^2 b^2+3 b^4\right ) x-\frac {a b \left (19 a^2+16 b^2\right ) \cos (e+f x)}{6 f}-\frac {b^2 \left (26 a^2+9 b^2\right ) \cos (e+f x) \sin (e+f x)}{24 f}-\frac {7 a b \cos (e+f x) (a+b \sin (e+f x))^2}{12 f}-\frac {b \cos (e+f x) (a+b \sin (e+f x))^3}{4 f}\\ \end {align*}
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Mathematica [A] time = 0.37, size = 106, normalized size = 0.77 \[ \frac {-96 a b \left (4 a^2+3 b^2\right ) \cos (e+f x)+3 \left (-8 \left (6 a^2 b^2+b^4\right ) \sin (2 (e+f x))+4 \left (8 a^4+24 a^2 b^2+3 b^4\right ) (e+f x)+b^4 \sin (4 (e+f x))\right )+32 a b^3 \cos (3 (e+f x))}{96 f} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.48, size = 106, normalized size = 0.77 \[ \frac {32 \, a b^{3} \cos \left (f x + e\right )^{3} + 3 \, {\left (8 \, a^{4} + 24 \, a^{2} b^{2} + 3 \, b^{4}\right )} f x - 96 \, {\left (a^{3} b + a b^{3}\right )} \cos \left (f x + e\right ) + 3 \, {\left (2 \, b^{4} \cos \left (f x + e\right )^{3} - {\left (24 \, a^{2} b^{2} + 5 \, b^{4}\right )} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{24 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.17, size = 112, normalized size = 0.82 \[ \frac {a b^{3} \cos \left (3 \, f x + 3 \, e\right )}{3 \, f} + \frac {b^{4} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} + \frac {1}{8} \, {\left (8 \, a^{4} + 24 \, a^{2} b^{2} + 3 \, b^{4}\right )} x - \frac {{\left (4 \, a^{3} b + 3 \, a b^{3}\right )} \cos \left (f x + e\right )}{f} - \frac {{\left (6 \, a^{2} b^{2} + b^{4}\right )} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.22, size = 116, normalized size = 0.85 \[ \frac {b^{4} \left (-\frac {\left (\sin ^{3}\left (f x +e \right )+\frac {3 \sin \left (f x +e \right )}{2}\right ) \cos \left (f x +e \right )}{4}+\frac {3 f x}{8}+\frac {3 e}{8}\right )-\frac {4 a \,b^{3} \left (2+\sin ^{2}\left (f x +e \right )\right ) \cos \left (f x +e \right )}{3}+6 a^{2} b^{2} \left (-\frac {\sin \left (f x +e \right ) \cos \left (f x +e \right )}{2}+\frac {f x}{2}+\frac {e}{2}\right )-4 a^{3} b \cos \left (f x +e \right )+a^{4} \left (f x +e \right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.07, size = 113, normalized size = 0.82 \[ a^{4} x + \frac {3 \, {\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} a^{2} b^{2}}{2 \, f} + \frac {4 \, {\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} a b^{3}}{3 \, f} + \frac {{\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} b^{4}}{32 \, f} - \frac {4 \, a^{3} b \cos \left (f x + e\right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 6.95, size = 114, normalized size = 0.83 \[ \frac {\frac {3\,b^4\,\sin \left (4\,e+4\,f\,x\right )}{4}-6\,b^4\,\sin \left (2\,e+2\,f\,x\right )+8\,a\,b^3\,\cos \left (3\,e+3\,f\,x\right )-36\,a^2\,b^2\,\sin \left (2\,e+2\,f\,x\right )-72\,a\,b^3\,\cos \left (e+f\,x\right )-96\,a^3\,b\,\cos \left (e+f\,x\right )+24\,a^4\,f\,x+9\,b^4\,f\,x+72\,a^2\,b^2\,f\,x}{24\,f} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.67, size = 240, normalized size = 1.75 \[ \begin {cases} a^{4} x - \frac {4 a^{3} b \cos {\left (e + f x \right )}}{f} + 3 a^{2} b^{2} x \sin ^{2}{\left (e + f x \right )} + 3 a^{2} b^{2} x \cos ^{2}{\left (e + f x \right )} - \frac {3 a^{2} b^{2} \sin {\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {4 a b^{3} \sin ^{2}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{f} - \frac {8 a b^{3} \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac {3 b^{4} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac {3 b^{4} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} + \frac {3 b^{4} x \cos ^{4}{\left (e + f x \right )}}{8} - \frac {5 b^{4} \sin ^{3}{\left (e + f x \right )} \cos {\left (e + f x \right )}}{8 f} - \frac {3 b^{4} \sin {\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} & \text {for}\: f \neq 0 \\x \left (a + b \sin {\relax (e )}\right )^{4} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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